Let's solve the problem step by step:
Let X be the number of games they played last season.
According to the problem, Ahmadullah's basketball team played 12 games more than 13 times the number of games they played last season.
So, 13X + 12 = 21.
Let's solve for X:
13X + 12 = 21
Subtract 12 from both sides:
13X = 9
Divide both sides by 13:
X = 9/13
Since the number of games played must be a whole number, we round down to the nearest whole number. Therefore, Ahmadullah's basketball team played 11 games last season.
So the answer is:
11 games.
Solve the following real-world problem: Ahmadullah’s basketball team will play 21 games this season. That is 12 games more than 13 the number of games they played last season. How many games did they play last season?(1 point)
Responses
27 games
27 games
33 games
33 games
11 games
11 games
7 games
3 answers
Joseph wants to buy tickets for the baseball game and a team hat to wear to the game. He has $34.25. If the hat costs $12.50 and tickets cost $7.25 each, how many tickets can he buy?(1 point)
Responses
2 tickets
2 tickets
6 tickets
6 tickets
3 tickets
3 tickets
1 ticket
Responses
2 tickets
2 tickets
6 tickets
6 tickets
3 tickets
3 tickets
1 ticket
Let's solve the problem step by step:
Joseph has $34.25.
The hat costs $12.50.
The tickets cost $7.25 each.
First, let's subtract the cost of the hat from Joseph's total amount:
$34.25 - $12.50 = $21.75
Now, let's divide the remaining amount by the cost of each ticket to determine how many tickets Joseph can buy:
$21.75 / $7.25 = 3
Therefore, Joseph can buy 3 tickets.
So the answer is:
3 tickets.
Joseph has $34.25.
The hat costs $12.50.
The tickets cost $7.25 each.
First, let's subtract the cost of the hat from Joseph's total amount:
$34.25 - $12.50 = $21.75
Now, let's divide the remaining amount by the cost of each ticket to determine how many tickets Joseph can buy:
$21.75 / $7.25 = 3
Therefore, Joseph can buy 3 tickets.
So the answer is:
3 tickets.