(1) SinB=Cos35 degrees
Draw the triangle. COsine = SINE of COmplement: 55°
(2) Cos286 degrees
= cos(270+16) = cos270cos16 - sin270sin16 = sin16°
(3) SinB=Cos3B
sinB-cos3B = 0
sin(π/2-B)-cos(3B)=0
now using the sum-to product formulas, that gives
2sin(B-π/4)sin(2B-π/4) = 0
So, since sin(0) = sin(π) = 0, just solve for B
(4) Cos2B=Sin3B
same way as above
(5) Cos y= Sin(y+22 degrees)
90-y = y+22
y = 34°
Solve the following questions
(1) SinB=Cos35 degrees
(2) Cos286 degrees
(3) SinB=Cos3B
(4) Cos2B=Sin3B
(5) Cos y= Sin(y+22 degrees)
1 answer