The quadratic formula is given by:
x = (-b ± √(b² - 4ac)) / (2a)
In the given quadratic equation -2x² - 7x + 13 = 0, we have:
a = -2, b = -7, c = 13
Plugging these values into the quadratic formula:
x = (-(-7) ± √((-7)² - 4(-2)(13))) / (2(-2))
= (7 ± √(49 + 104)) / (-4)
= (7 ± √(153)) / (-4)
Therefore, the solution to the quadratic equation -2x² - 7x + 13 = 0 is:
x = (7 ± √(153)) / (-4)
x = (7 - √(153)) / (-4) and x = (7 + √(153)) / (-4)
Solve the following quadratic equation using the quadratic formula. −2x2−7x+13=0 **Note: Make sure to enter both solutions together in the space provided using the ± symbol. For example: x={12±√10} (1 point) show all your work
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