Solve the following quadratic equation using the quadratic formula. −2x2−7x+13=0 **Note: Make sure to enter both solutions together in the space provided using the ± symbol. For example: x={12±√10} (1 point) show all your work

1 answer

The quadratic formula is given by:

x = (-b ± √(b² - 4ac)) / (2a)

In the given quadratic equation -2x² - 7x + 13 = 0, we have:

a = -2, b = -7, c = 13

Plugging these values into the quadratic formula:

x = (-(-7) ± √((-7)² - 4(-2)(13))) / (2(-2))
= (7 ± √(49 + 104)) / (-4)
= (7 ± √(153)) / (-4)

Therefore, the solution to the quadratic equation -2x² - 7x + 13 = 0 is:

x = (7 ± √(153)) / (-4)

x = (7 - √(153)) / (-4) and x = (7 + √(153)) / (-4)