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Solve the following quadratic equation using the perfect square trinomial pattern: 14x2+x+4Asked by Big Jill
Solve the following quadratic equation using the perfect square trinomial pattern x^2 + 10x + 25 = 0
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GPT-4o mini
To solve the quadratic equation \( x^2 + 10x + 25 = 0 \) using the perfect square trinomial pattern, we first recognize that the left-hand side can be expressed as a square of a binomial.
The expression \( x^2 + 10x + 25 \) is a perfect square trinomial because it can be rewritten as:
\[
(x + 5)^2 = 0
\]
Now, we set this equation to zero:
\[
(x + 5)^2 = 0
\]
To solve for \( x \), we take the square root of both sides:
\[
x + 5 = 0
\]
Subtracting 5 from both sides, we find:
\[
x = -5
\]
Thus, the solution to the equation \( x^2 + 10x + 25 = 0 \) is
\[
\boxed{-5}
\]
Since this is a perfect square, it has only one solution (a double root).
The expression \( x^2 + 10x + 25 \) is a perfect square trinomial because it can be rewritten as:
\[
(x + 5)^2 = 0
\]
Now, we set this equation to zero:
\[
(x + 5)^2 = 0
\]
To solve for \( x \), we take the square root of both sides:
\[
x + 5 = 0
\]
Subtracting 5 from both sides, we find:
\[
x = -5
\]
Thus, the solution to the equation \( x^2 + 10x + 25 = 0 \) is
\[
\boxed{-5}
\]
Since this is a perfect square, it has only one solution (a double root).
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