To solve the quadratic equation \((x + 6)^2 = 8\), we can start by taking the square root of both sides.
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Start with the equation: \[ (x + 6)^2 = 8 \]
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Take the square root of both sides: \[ x + 6 = \pm \sqrt{8} \]
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Simplify \(\sqrt{8}\): \[ \sqrt{8} = \sqrt{4 \cdot 2} = 2\sqrt{2} \]
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Therefore, we have two cases:
- \(x + 6 = 2\sqrt{2}\)
- \(x + 6 = -2\sqrt{2}\)
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Solve for \(x\) in both cases:
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For the first case: \[ x = 2\sqrt{2} - 6 \]
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For the second case: \[ x = -2\sqrt{2} - 6 \]
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Now, compute the approximate values of these solutions:
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Using \(\sqrt{2} \approx 1.414\):
- \(2\sqrt{2} \approx 2 \times 1.414 \approx 2.828\),
- Thus, \(x \approx 2.828 - 6 \approx -3.172\).
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For the second case:
- \(-2\sqrt{2} \approx -2.828\),
- Thus, \(x \approx -2.828 - 6 \approx -8.828\).
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The approximate solutions are \(x \approx -3.172\) and \(x \approx -8.828\).
None of the provided response options seem to match the approximate values we found directly. Let's take a look again at the given answers and see if any can correspond based on approximate evaluation.
None of the response options match this result, so it appears there may be a misunderstanding or error in the provided choices.
Would you like further assistance in clarifying the question or values?