Asked by mis_input!!!! calm down!
solve the following quadratic equation using square roots -9+(x-3)^2/-4 = -4
{28,-22}
{8,-2}
{16,-10}
{2,-8}
{28,-22}
{8,-2}
{16,-10}
{2,-8}
Answers
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Answered by
GPT-4o mini
To solve the quadratic equation using square roots, we start with the given equation:
\[
\frac{-9 + (x - 3)^2}{-4} = -4
\]
First, we can multiply both sides of the equation by -4 to eliminate the fraction:
\[
-9 + (x - 3)^2 = 16
\]
Next, we'll move -9 to the other side of the equation:
\[
(x - 3)^2 = 16 + 9
\]
\[
(x - 3)^2 = 25
\]
Now, we take the square root of both sides:
\[
x - 3 = \pm 5
\]
This gives us two equations to solve:
1. \(x - 3 = 5\)
2. \(x - 3 = -5\)
Solving the first equation:
\[
x = 5 + 3 = 8
\]
Solving the second equation:
\[
x = -5 + 3 = -2
\]
Therefore, the solutions to the equation are:
\[
\{8, -2\}
\]
The correct answer is:
\(\{8, -2\}\)
\[
\frac{-9 + (x - 3)^2}{-4} = -4
\]
First, we can multiply both sides of the equation by -4 to eliminate the fraction:
\[
-9 + (x - 3)^2 = 16
\]
Next, we'll move -9 to the other side of the equation:
\[
(x - 3)^2 = 16 + 9
\]
\[
(x - 3)^2 = 25
\]
Now, we take the square root of both sides:
\[
x - 3 = \pm 5
\]
This gives us two equations to solve:
1. \(x - 3 = 5\)
2. \(x - 3 = -5\)
Solving the first equation:
\[
x = 5 + 3 = 8
\]
Solving the second equation:
\[
x = -5 + 3 = -2
\]
Therefore, the solutions to the equation are:
\[
\{8, -2\}
\]
The correct answer is:
\(\{8, -2\}\)
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