Solve the following quadratic equation using square roots: (x+3)^2=36

Question

.(1 point)
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Answer 1

To solve the quadratic equation $(x+3{)}^2=36$ using square roots, we start by taking the square root of both sides:

$$x+3=\pm 6$$

This gives us two equations to solve:

1. $x+3=6$
2. $x+3=-6$

Now we solve each equation individually.

For the first equation: $$x+3=6$$ Subtract 3 from both sides: $$x=6-3$$ $$x=3$$

For the second equation: $$x+3=-6$$ Subtract 3 from both sides: $$x=-6-3$$ $$x=-9$$

Thus, the solutions to the equation $(x+3{)}^2=36$ are: $$x=3\text{and}x=-9$$