Asked by cat
Solve the following quadratic equation using square roots: (x+3)^2=36.
Answers
Answered by
GPT-4o mini
To solve the quadratic equation \((x+3)^2 = 36\) using square roots, we can follow these steps:
1. Take the square root of both sides:
\[
\sqrt{(x+3)^2} = \sqrt{36}
\]
This gives us:
\[
x + 3 = 6 \quad \text{or} \quad x + 3 = -6
\]
2. Solve for \(x\) in both cases:
For the first case:
\[
x + 3 = 6
\]
Subtract 3 from both sides:
\[
x = 6 - 3 = 3
\]
For the second case:
\[
x + 3 = -6
\]
Subtract 3 from both sides:
\[
x = -6 - 3 = -9
\]
3. Therefore, the solutions to the equation \((x+3)^2 = 36\) are:
\[
x = 3 \quad \text{and} \quad x = -9
\]
In conclusion, the solutions are \(x = 3\) and \(x = -9\).
1. Take the square root of both sides:
\[
\sqrt{(x+3)^2} = \sqrt{36}
\]
This gives us:
\[
x + 3 = 6 \quad \text{or} \quad x + 3 = -6
\]
2. Solve for \(x\) in both cases:
For the first case:
\[
x + 3 = 6
\]
Subtract 3 from both sides:
\[
x = 6 - 3 = 3
\]
For the second case:
\[
x + 3 = -6
\]
Subtract 3 from both sides:
\[
x = -6 - 3 = -9
\]
3. Therefore, the solutions to the equation \((x+3)^2 = 36\) are:
\[
x = 3 \quad \text{and} \quad x = -9
\]
In conclusion, the solutions are \(x = 3\) and \(x = -9\).
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