To solve the quadratic equation \((x + 12)^2 = 9\) using square roots, follow these steps:
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Take the square root of both sides: \[ x + 12 = \pm 3 \]
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This gives us two separate equations to solve: \[ x + 12 = 3 \quad \text{and} \quad x + 12 = -3 \]
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Solve each equation for \(x\):
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For \(x + 12 = 3\): \[ x = 3 - 12 \] \[ x = -9 \]
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For \(x + 12 = -3\): \[ x = -3 - 12 \] \[ x = -15 \]
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Thus, the solutions to the equation \((x + 12)^2 = 9\) are: \[ x = -9 \quad \text{and} \quad x = -15 \]
Therefore, the solution set is \({-9, -15}\).
The correct response is: \({-9, -15}\)