To solve the quadratic equation x² + 3x = 18 by factoring, we need to rearrange it to the form ax² + bx + c = 0 and then factor it.
Starting with x² + 3x - 18 = 0, we can factor it as (x + 6)(x - 3) = 0.
Now, set each factor equal to zero and solve for x:
x + 6 = 0
x = -6
x - 3 = 0
x = 3
So, the solutions to the quadratic equation are x1 = -6 and x2 = 3.
Solve the following quadratic equation by factoring.
x²+3x=18
Write from least to greatest. Example, x1 would be the smallest solution and x2 would be the largest.
x1 =
x2 =
1 answer
1 answer