solve the following quadratic equation by factoring

x^2+3x=18

please type your answers from least to gratest for ex x1 be smallest and x2 be the greatest
show all the steps

1 answer

To solve the equation x^2 + 3x = 18 by factoring:

Step 1: Move all terms to one side of the equation to set it equal to zero:
x^2 + 3x - 18 = 0

Step 2: Factor the quadratic expression on the left side of the equation:
(x + 6)(x - 3) = 0

Step 3: Set each factor equal to zero and solve for x:
x + 6 = 0 -> x = -6
x - 3 = 0 -> x = 3

Therefore, the solutions to the quadratic equation x^2 + 3x = 18 are:
x1 = -6
x2 = 3