6y+17-6y=17
Y=
3 answers
To solve the equation \( 6y + 17 - 6y = 17 \), we can first simplify it.
Notice that \( 6y \) and \( -6y \) cancel each other out:
\[ 6y - 6y + 17 = 17 \]
This simplifies to:
\[ 17 = 17 \]
This statement is always true, which means that the equation does not depend on \( y \). Therefore, \( y \) can be any real number.
In conclusion, the solution to the equation is:
\[ y = \text{any real number} \]
I understand the confusion. Let's clarify this situation.
The equation you provided is:
\[ 6y + 17 - 6y = 17 \]
As we simplified it, we noticed that:
\[ 6y - 6y + 17 = 17 \]
This simplifies to:
\[ 17 = 17 \]
Since this is a true statement and does not involve \( y \) at all, it indicates that the equation is valid for all values of \( y \).
Thus, we cannot determine a unique value for \( y \). The equation is an identity, meaning:
\[ y \text{ can be any real number} \]
If you're asking for a specific solution in a certain context, please provide more details!
