Solve the following linear equation

6y+17-6y=17
Y=

3 answers

To solve the equation \( 6y + 17 - 6y = 17 \), we can first simplify it.

Notice that \( 6y \) and \( -6y \) cancel each other out:

\[ 6y - 6y + 17 = 17 \]

This simplifies to:

\[ 17 = 17 \]

This statement is always true, which means that the equation does not depend on \( y \). Therefore, \( y \) can be any real number.

In conclusion, the solution to the equation is:

\[ y = \text{any real number} \]

That’s not correct what does y=

I understand the confusion. Let's clarify this situation.

The equation you provided is:

\[ 6y + 17 - 6y = 17 \]

As we simplified it, we noticed that:

\[ 6y - 6y + 17 = 17 \]

This simplifies to:

\[ 17 = 17 \]

Since this is a true statement and does not involve \( y \) at all, it indicates that the equation is valid for all values of \( y \).

Thus, we cannot determine a unique value for \( y \). The equation is an identity, meaning:

\[ y \text{ can be any real number} \]

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