solve the following for x, where 0<x<2pi.... 2tanx+ sq rt 12=0

Question

- write the general solution aswell

Answer 1

2 tanx = -√12
tanx = -√12/2
x = 60° or 240°
since the period of tanx is 180°
the general solution would be 60° + 180k

now I will switch to radians
x = π/3 or 4π/3
general solution : x = π/3 + kπ , where k is an integer

(I used my calculator to find the first angle, even though I should have recognized √12/2 as √3
I usually set my calculator to degrees, that way I recognize the standard angles if there are any.
Unless you recognize the decimal versions of radian angles, this works best for me)