Asked by Nicole
solve the following for x, where 0<x<2pi.... 2tanx+ sq rt 12=0
- write the general solution aswell
- write the general solution aswell
Answers
Answered by
Reiny
2 tanx = -√12
tanx = -√12/2
x = 60° or 240°
since the period of tanx is 180°
the general solution would be 60° + 180k
now I will switch to radians
x = π/3 or 4π/3
general solution : x = π/3 + kπ , where k is an integer
(I used my calculator to find the first angle, even though I should have recognized √12/2 as √3
I usually set my calculator to degrees, that way I recognize the standard angles if there are any.
Unless you recognize the decimal versions of radian angles, this works best for me)
tanx = -√12/2
x = 60° or 240°
since the period of tanx is 180°
the general solution would be 60° + 180k
now I will switch to radians
x = π/3 or 4π/3
general solution : x = π/3 + kπ , where k is an integer
(I used my calculator to find the first angle, even though I should have recognized √12/2 as √3
I usually set my calculator to degrees, that way I recognize the standard angles if there are any.
Unless you recognize the decimal versions of radian angles, this works best for me)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.