solve the following equations:

Question

y^2-1/4y=0

Answer 1

If y^2-1/4y=0 mean :

y ^ 2 - ( 1 / 4 ) y = 0 then :

Write y ^ 2 like :

4 y ^ 2 / 4

Now :

4 y ^ 2 / 4 - ( 1 / 4 ) y = 0

( 1 / 4 ) 4 y - ( 1 / 4 ) y = 0

( 1 / 4 ) ( 4 y ^ 2 - y ) = 0

( 1 / 4 ) y ( 4 y - 1 ) = 0

Now you must solwe two equations :

( 1 / 4 ) y = 0

and

4 y - 1 = 0

( 1 / 4 ) y = 0 Multiply both sides by 4

y = 0

4 y - 1 = 0 Add 1 to both sides

4 y - 1 + 1 = 0 + 1

4 y = 1 Divide both sides by 4

y = 1 / 4

The solutions are :

y = 0 and y = 1 / 4