Solve the following equation with a rational exponent: 2x32=16 .(1 point)

Responses

no solution
no solution

8
8

4
4

84
84

1 answer

To solve the equation \( 2x^{3/2} = 16 \), follow these steps:

  1. Isolate the term with the variable:

    Divide both sides by 2: \[ x^{3/2} = \frac{16}{2} \] \[ x^{3/2} = 8 \]

  2. Remove the rational exponent:

    To get rid of the exponent \(\frac{3}{2}\), we can raise both sides of the equation to the reciprocal of \(\frac{3}{2}\), which is \(\frac{2}{3}\): \[ (x^{3/2})^{\frac{2}{3}} = 8^{\frac{2}{3}} \]

    The left side simplifies: \[ x^{(3/2) \cdot (2/3)} = x^{1} = x \]

    Now we need to calculate \(8^{\frac{2}{3}}\). This can be done as follows: \[ 8^{\frac{2}{3}} = (8^{\frac{1}{3}})^2 \]

    Since \(8^{\frac{1}{3}} = 2\) (because \(2^3 = 8\)), we have: \[ 8^{\frac{2}{3}} = (2)^2 = 4 \]

  3. Final Result: \[ x = 4 \]

Thus, the solution is \(\boxed{4}\).

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