Solve the following equation: 2(x+2)=4^2. What is the missing value?

Answer 1

To solve the equation \(2(x+2) = 4^2\), we can start by simplifying the right-hand side.

First, calculate \(4^2\): \[ 4^2 = 16 \]

Now, the equation becomes: \[ 2(x+2) = 16 \]

Next, we can divide both sides of the equation by 2 to isolate \(x + 2\): \[ x + 2 = \frac{16}{2} \] \[ x + 2 = 8 \]

Now, subtract 2 from both sides to solve for \(x\): \[ x = 8 - 2 \] \[ x = 6 \]

Thus, the missing value is \(\boxed{6}\).