are you saying that
2^(2x+8) = - [ 2^5]^(2x+1)
then
2x+8 = -5 (2x+1)
2 x + 8 = -10 x - 5
12 x = - 13
x = -13/12
solve the ff indical equation: 2^(2x+8)-32^(2x+1)=0
2.4^x=0.59
2 answers
2^(2x+8)-32^(2x+1)=0
2^(2x+8) = 32^(2x+1)
2^(2x+8) = 2^(10x+5)
2x+8 = 10x+5
8x = 3
x = 3/8
2.4^x=0.59
x log2.4 = log0.59
x = log0.59/log2.4 = -0.6
2^(2x+8) = 32^(2x+1)
2^(2x+8) = 2^(10x+5)
2x+8 = 10x+5
8x = 3
x = 3/8
2.4^x=0.59
x log2.4 = log0.59
x = log0.59/log2.4 = -0.6
3 answers