To solve the factored quadratic equation \((x-5)(x+3) = 0\), we can use the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero.
We set each factor equal to zero:
- \(x - 5 = 0\)
- \(x + 3 = 0\)
Now, we solve each equation:
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For \(x - 5 = 0\): \[ x = 5 \]
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For \(x + 3 = 0\): \[ x = -3 \]
Thus, the solutions to the equation \((x-5)(x+3) = 0\) are: \[ x = 5 \quad \text{and} \quad x = -3 \]
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