To solve the factored quadratic equation \((19x−3)(9+x) = 0\), we set each factor equal to zero:
- \(19x - 3 = 0\)
- \(9 + x = 0\)
Solving the first equation:
\[ 19x - 3 = 0 \implies 19x = 3 \implies x = \frac{3}{19} \]
Solving the second equation:
\[ 9 + x = 0 \implies x = -9 \]
So the solutions to the equation are:
\[ x = -9 \quad \text{and} \quad x = \frac{3}{19} \]
The solution set is:
\[ x = {-9, \frac{3}{19}} \]
Therefore, the correct response is:
The solution set is \(x\) is equal to negative 9 comma \(3\) over \(19\).
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