To solve the factored quadratic equation \((13x+3)(9x−14)=0\), we set each factor equal to zero:
- \(13x + 3 = 0\)
- \(9x - 14 = 0\)
Now we solve each equation:
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For \(13x + 3 = 0\): \[ 13x = -3 \ x = -\frac{3}{13} \]
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For \(9x - 14 = 0\): \[ 9x = 14 \ x = \frac{14}{9} \]
So, the solution set is: \[ x = \left{ -\frac{3}{13}, \frac{14}{9} \right} \]
Thus, the correct response is: The solution set is \(x = \left{ -\frac{3}{13}, \frac{14}{9} \right}\).