Solve the expression of 15 times 8 to the power of 0 / 5 + 4 (7 to the power of 0 minus 6)

1 answer

Let's solve the expression step by step:

The given expression is:

\[ 15 \times 8^0 / 5 + 4 \times (7^0 - 6) \]

Step 1: Calculate \(8^0\) and \(7^0\).

By definition, any non-zero number raised to the power of 0 is 1.

\[ 8^0 = 1 \quad \text{and} \quad 7^0 = 1 \]

Step 2: Substitute these values back into the expression.

\[ 15 \times 1 / 5 + 4 \times (1 - 6) \]

Now the expression simplifies to:

\[ 15 / 5 + 4 \times (-5) \]

Step 3: Divide \(15\) by \(5\).

\[ 3 + 4 \times (-5) \]

Step 4: Calculate \(4 \times (-5)\).

\[ 4 \times (-5) = -20 \]

Step 5: Substitute back into the expression.

\[ 3 - 20 \]

Step 6: Finally, calculate \(3 - 20\).

\[ 3 - 20 = -17 \]

Thus, the final result of the expression is:

\[ \boxed{-17} \]