3 = x-3
6 = x
As for the other, I can't quite decode your weird text. I can say that
ln e = 1
ln √n = 1/2 ln n
ln a - ln b = ln(a/b)
If you have
ln e = ln √6 - 3ln x
1 = ln√6 - ln x^3
1 = ln √(6/x^6)
e = √(6/x^6)
6/x^6 = e^2
x^6 = 6/e^2
x = (6/e^2)^(1/6)
I suspect that is not what you were after, but it should show you how to manipulate logs a little.
Solve the equations by finding the exact solution.
a 3= x -3 what is x
b In e = In like a check mark 7 with a 6 under the 7 -3 In e x is what
Thank you very much for your time
2 answers
thank you Steve it does give me a direction in which to guide me.