if the roots are a,2a,b then
a+2a+b = 7
2a^2b = -36
a*2a + ab + 2ab = 0
or, a(2a+3b) = 0
so, b = -2a/3
Solve those and you find 3,6,-2
solve the equation x³ − 7x² + 36 = 0 , given that one root is double the other
2 answers
3,6,-2
1 answer