Solve the equation −(x−3)^2−3 =7 and re-express the answer as a complex number in the standard from a±bi .(1 point)

3 answers

To solve the equation \(- (x - 3)^2 - 3 = 7\), we can start by isolating the quadratic term.

  1. Add 3 to both sides of the equation: \[

    • (x - 3)^2 = 7 + 3 \] \[
    • (x - 3)^2 = 10 \]
  2. Multiply both sides by -1: \[ (x - 3)^2 = -10 \]

  3. Now, take the square root of both sides: \[ x - 3 = \pm \sqrt{-10} \] Using the fact that \(\sqrt{-10} = i\sqrt{10}\) (where \(i = \sqrt{-1}\)): \[ x - 3 = \pm i\sqrt{10} \]

  4. Solve for \(x\): \[ x = 3 \pm i\sqrt{10} \]

Thus, the solutions are: \[ x = 3 + i\sqrt{10} \quad \text{and} \quad x = 3 - i\sqrt{10} \]

Expressing the answer in the standard form \(a + bi\):

  1. For \(x = 3 + i\sqrt{10}\), we have \(a = 3\) and \(b = \sqrt{10}\).
  2. For \(x = 3 - i\sqrt{10}\), we have \(a = 3\) and \(b = -\sqrt{10}\).

So the solutions in the standard form \(a \pm bi\) are: \[ x = 3 + i\sqrt{10} \quad \text{and} \quad x = 3 - i\sqrt{10} \]

Its a blank what would you like me to put not mutiple choice

If you're looking for a single answer to fill in the blank, you can write it in the standard form \(a + bi\) or \(a - bi\). Here's what you can put in the blank:

  1. For the first solution: \[ 3 + i\sqrt{10} \]

  2. For the second solution: \[ 3 - i\sqrt{10} \]

You can choose either of these two solutions to fill in the blank. If only one entry is allowed, you could go with:

\[ 3 + i\sqrt{10} \]

Or, if your context specifies to prefer the negative imaginary part, you could use:

\[ 3 - i\sqrt{10} \]

Just pick one of these forms depending on what is required.