use the quadratic formula
the roots are not real numbers
Solve the equation x^2-2x+3=0
2 answers
completing the square works nice here
x^2-2x+3=0
x^2 - 2x + 1 = -3 + 1
(x-1)^2 = -2
x - 1 = ± i√2
x = 1 ± i√2
x^2-2x+3=0
x^2 - 2x + 1 = -3 + 1
(x-1)^2 = -2
x - 1 = ± i√2
x = 1 ± i√2