Let's solve the equation step by step:
The original equation is:
\[ 2(x + 8) = 2x + 8 \]
Step 1: Distribute the left side of the equation.
\[ 2 \cdot x + 2 \cdot 8 = 2x + 8 \] \[ 2x + 16 = 2x + 8 \]
So the Resulting Equation is: \(2x + 16 = 2x + 8\).
Step 2: Subtract \(2x\) from both sides of the equation.
\[ 2x + 16 - 2x = 2x + 8 - 2x \] \[ 16 = 8 \]
So the Resulting Equation is: \(16 = 8\).
Step 3: Since \(16 = 8\) is a false statement, there are no solutions.
So the answer for types of solutions is: "no solution".
Putting it all together:
- Step 1: Resulting Equation: \(2x + 16 = 2x + 8\)
- Step 2: Resulting Equation: \(16 = 8\)
- Step 3: There are no solution(s).