well, you must have
tan2x = 0
or sinx = 1
so, you are almost right. tan2x=0 if 2x = 0 or π or 2π or 3π
so, x = 0, π/2, π, 3π/2
sinx = 1 if x = π/2, so that does not add any solutions to the list.
Solve the equation on the interval [0, 2π).
tan2x sin x = tan2x
would it be 0, pi/2 ?
1 answer