3x-2/x-5 = 2^4
3x-2/x-5 = 16
multiply by x-5
x-5(3x-2/x-5) = 16(x-5)
3x -2 = 16x -80
3x -16x -2 16x-16x -80
-13x -2 = -80
-13x -2 + 2 = -80 +2
-13x = -78
x = 6
solve the equation
log2(3x-2) - log2 (x-5)=4
1 answer