Solve the equation. Identify any extraneous solutions.

Question

x = sqrt root 3x + 40

Answer 1

X = sqrt(3X+40),
Square both sides:
X^2 = 3X + 40,
X^2 - 3X - 40 = 0,
X-8)(X+5) = 0,
X-5=0,
X = 5.

X+5 = 0,
X = -5.

Solution set: X = -5, and X = 5.

5 does not satisfy the original Eq.
Therefore, it is an extraneous solution.