maybe you mean
3^(2x) - 3^(x+2) + 8 = 0
let z = 3^x
z^2 - 9 z + 8 = 0
(z-8)(z-1) = 0
z = 1 or z = 8
x = 0 or x = 2
solve the equation for x.
3^2x - 3^x+2 +8 =0
Ps. The topic is logarithmic and exponential functions
1 answer