To solve the equation 2x^2 = 7x + 1 using the quadratic formula, we first rewrite it in standard form:
2x^2 - 7x - 1 = 0
Now we can identify the coefficients a, b, and c in the general quadratic equation ax^2 + bx + c = 0:
a = 2
b = -7
c = -1
The quadratic formula states that the solutions for x can be found using the formula:
x = [-b ± √(b^2 - 4ac)] / 2a
Plugging in the values from our equation gives:
x = [7 ± √((-7)^2 - 4(2)(-1))] / (2)(2)
x = [7 ± √(49 + 8)] / 4
x = [7 ± √57] / 4
Therefore, the solutions for x are:
x = (7 + √57) / 4
and
x = (7 - √57) / 4
Solve the equation for real solutions by the quadratic formula.
2x2=7x+1
1 answer