Solve the equation for 0≤ x ≤ 180 given tan(x) sin^2(x)=2tan(x)

How do I do this? Thank you and Merry Christmas! :)

3 answers

tan(x) sin^2(x)=2tan(x)
tanx(sin^2(x)-2) = 0

How about now?
I tried to continue the problem, but I'm stuck. What do I do from tanx(sin^2(x)-2) = 0 ?
oh come on. If ab=0, then either a=0 or b=0

So, we have

tanx = 0 --> x is a multiple of pi
or
sin^2(x) = 2 --> no solutions there.