Asked by Jayden Haddy
solve the equation
express the answers in p and q
x(square) - (p+q)x + (p+1)(q-1)=0
Then x=? or x=?
express the answers in p and q
x(square) - (p+q)x + (p+1)(q-1)=0
Then x=? or x=?
Answers
Answered by
Jai
Recall that in a quadratic equation,
x^2 - (sum of roots)x + (product of roots) = 0
or if we let a & b the roots,
x^2 - (a+b) + (a)(b) = 0
From the given equation, we can see that the constant term is factored, which is (p+1)(q-1). Now, let's assume that the roots are p+1 and q-1. We then check its sum if it is equal to p+q. If it is, then they are the roots of the equation:
p + 1 + q - 1 = p + q
Therefore the roots are p+1 and q+1.
Another way to solve this is to use the quadratic equation:
x = [-b +/- sqrt(b^2 - 4ac)] / 2a
You should get the same answer.
Hope this helps~ :)
x^2 - (sum of roots)x + (product of roots) = 0
or if we let a & b the roots,
x^2 - (a+b) + (a)(b) = 0
From the given equation, we can see that the constant term is factored, which is (p+1)(q-1). Now, let's assume that the roots are p+1 and q-1. We then check its sum if it is equal to p+q. If it is, then they are the roots of the equation:
p + 1 + q - 1 = p + q
Therefore the roots are p+1 and q+1.
Another way to solve this is to use the quadratic equation:
x = [-b +/- sqrt(b^2 - 4ac)] / 2a
You should get the same answer.
Hope this helps~ :)
Answered by
Jai
*I mean the roots are p+1 and q-1.
Just a typo error. Sorry about that. :3
Just a typo error. Sorry about that. :3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.