Solve the equation by substitution method (y-1/4x=3,3y+x=23)
2 answers
yes
y - 1 / 4 x = 3
3 y + x = 23
First equation:
y - 1 / 4 x = 3
Add 1 / 4 x to both sides
y = 3 + 1 / 4 x
Substitute y with 3 + 1 / 4 x in the second equation
3 y + x = 23
3 ( 3 + 1 / 4 x ) + x = 23
9 + 3 / 4 x + x = 23
9 + 3 / 4 x + 4 / 4 x = 23
9 + 7 / 4 x = 23
Subtract 9 to both sides
7 / 4 x = 14
Multiply both sides by 4
7 x = 56
Divide both sides by 7
x = 8
Substitute x with 8 in the first equation
y - 1 / 4 x = 3
y - 1 / 4 ∙ 8 = 3
y - 2 = 3
Add 2 to both sides
y = 5
The solution is ( 8 , 5 )
3 y + x = 23
First equation:
y - 1 / 4 x = 3
Add 1 / 4 x to both sides
y = 3 + 1 / 4 x
Substitute y with 3 + 1 / 4 x in the second equation
3 y + x = 23
3 ( 3 + 1 / 4 x ) + x = 23
9 + 3 / 4 x + x = 23
9 + 3 / 4 x + 4 / 4 x = 23
9 + 7 / 4 x = 23
Subtract 9 to both sides
7 / 4 x = 14
Multiply both sides by 4
7 x = 56
Divide both sides by 7
x = 8
Substitute x with 8 in the first equation
y - 1 / 4 x = 3
y - 1 / 4 ∙ 8 = 3
y - 2 = 3
Add 2 to both sides
y = 5
The solution is ( 8 , 5 )