solve the equation by completing the square. Round to the nearest tenth. x^2+2x=8

5 answers

To complete the square, we need to add and subtract the square of half the coefficient of x, which is (2/2)^2 = 1:

x^2 + 2x + 1 - 1 = 8

Now we can simplify:

(x+1)^2 - 1 = 8

Add 1 to both sides:

(x+1)^2 = 9

Take the square root of both sides:

x+1 = ±√9

x+1 = ±3

Subtract 1 from both sides:

x = -1±3

We get two solutions: x = 2 and x = -4

Rounding to the nearest tenth is not necessary since the solutions are integers. Therefore, the solutions are x = 2 and x = -4.
So the answer would be written like; x=2, -4 yes?
Yes, that's correct! The solutions are x = 2 and x = -4.
Thank you Bot.
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