Solve the equation.
b^2+12b+36=48
3 answers
using quadratic formula before that subtract 36 from 48
b^2 + 12b + 36-48 = 0.
b^2 + 12b - 12 = 0
Use Quadratic formula:
b = (-B +- sqrt(B^2-4AC))/2A.
b = (-12 +- sqrt(12^2+48))/2 = ?.
You should get 0.928, and -12.928.
Note: 48 is positive, because we are subtracting a -48.
b^2 + 12b - 12 = 0
Use Quadratic formula:
b = (-B +- sqrt(B^2-4AC))/2A.
b = (-12 +- sqrt(12^2+48))/2 = ?.
You should get 0.928, and -12.928.
Note: 48 is positive, because we are subtracting a -48.
find the orthogonal trajectories of the family of circles x2+y2+2fy+1=0 f being a parameter
2 answers