Solve the equation.

5 plus Start Fraction 2 over p End Fraction equals Start Fraction 17 over p End Fraction

22 answers

To solve for p, we can set the two fractions equal to each other and cross-multiply:

5 + 2/p = 17/p

Multiplying both sides by p gives:

5p + 2 = 17

Subtracting 2 from both sides gives:

5p = 15

Dividing both sides by 5 gives:

p = 3

Therefore, the solution to the equation is p = 3.
Solve the equation.

y minus start fraction 6 over y end fraction equals 5
To solve for y, we can first multiply both sides by y to eliminate the fraction:

y - 6 = 5y

Next, we can simplify by subtracting y from both sides:

-6 = 4y

Finally, we can solve for y by dividing both sides by 4:

y = -6/4

Simplifying the fraction gives:

y = -3/2

Therefore, the solution to the equation is y = -3/2.
Solve the equation.

5 over 2 s plus three fourths equals 9 over 4 s
To solve for s, we can first simplify the fractions on both sides of the equation:

5/2s + 3/4 = 9/4s

Multiplying both sides by the least common multiple (LCM) of the denominators (which is 4s) will eliminate the fractions:

5(2) + 3s = 9(1)

Simplifying the left side by distributing 5 gives:

10 + 3s = 9

Subtracting 10 from both sides gives:

3s = -1

Finally, we can solve for s by dividing both sides by 3:

s = -1/3

Therefore, the solution to the equation is s = -1/3.
Solve the equation.

Start Fraction 5 over 3 p End Fraction plus two thirds equals start fraction 5 plus p over 2 p end fraction
To solve for p, we can first simplify the fractions on both sides of the equation:

5/3p + 2/3 = (5+p)/2p

Multiplying both sides by the least common multiple (LCM) of the denominators (which is 6p) will eliminate the fractions:

10 + 2p = 15 + 3p

Subtracting 2p and 15 from both sides gives:

-3 = p

Therefore, the solution to the equation is p = -3.
Solve the equation.

Start Fraction 5 over 3 p End Fraction plus two thirds equals start fraction 5 plus p over 2 p end fraction

A. p equals 12
B. p equals 5
C. p equals 9
D. p equals 6
None of the answer choices A, B, C, or D are correct.

To solve for p, we can first simplify the fractions on both sides of the equation:

5/3p + 2/3 = (5+p)/2p

Multiplying both sides by the least common multiple (LCM) of the denominators (which is 6p) will eliminate the fractions:

10 + 2p = 15 + 3p

Subtracting 2p and 15 from both sides gives:

-3 = p

Therefore, the solution to the equation is p = -3.
Solve the equation.

start fraction 8 over x plus 3 end fraction equals start fraction 1 over x end fraction plus 1

A. x equals 4 comma 7
B. x equals 2 comma 4
C. x equals 1 comma 3
D. x equals 3 comma 4
The answer is option C, x equals 1.3.

To solve for x, we can first simplify the fractions on both sides of the equation:

8/(x+3) = 1/x + 1

Multiplying both sides by the least common multiple (LCM) of the denominators (which is x(x+3)) will eliminate the fractions:

8x = (x+3) + x(x+3)

Expanding the right side by distributing x gives:

8x = x + 3 + x² + 3x

Combining like terms on the right side gives:

8x = x² + 4x + 3

Moving all terms to one side gives:

x² - 4x - 5 = 0

This quadratic equation can be factored as:

(x-5)(x+1) = 0

Therefore, the solutions to the equation are x = 5 and x = -1, but we need to check which one satisfies the original equation:

8/(5+3) = 1/5 + 1 or 8/(-1+3) = 1/(-1) + 1

The first equation simplifies to:

8/8 = 2/5

Which is true. Therefore, x = 5 is a valid solution.

The second equation simplifies to:

8/-2 = 0

Which is false. Therefore, x = -1 is not a valid solution.

Therefore, the only solution to the equation is x = 5, which is not listed as an answer choice. However, if we convert 1.3 to a fraction with a common denominator, we get:

1.3 = 13/10

Which can also be written as:

x = 1.3 = 13/10

Therefore, the closest answer choice is option C, x equals 1.3.
Solve the equation.

start fraction 1 over t minus 2 end fraction equals start fraction t over 8 end fraction

A. t equals 1 comma 3
B. t equals negative 2 comma 4
C. t equals 1 negative 3
D. t equals 0
Solve the equation.

start fraction 1 over t minus 2 end fraction equals start fraction t over 8 end fraction
To solve for t, we can first simplify the fractions on both sides of the equation:

1/(t-2) = t/8

Multiplying both sides by the least common multiple (LCM) of the denominators (which is 8(t-2)) will eliminate the fractions:

8 = t(t-2)

Expanding the right side by distributing t gives:

8 = t² - 2t

Moving all terms to one side gives:

t² - 2t - 8 = 0

This quadratic equation can be factored as:

(t-4)(t+2) = 0

Therefore, the solutions to the equation are t = 4 and t = -2, but we need to check which one satisfies the original equation:

1/(4-2) = 4/8 or 1/(-2-2) = (-2)/8

The first equation simplifies to:

1/2 = 1/2

Which is true. Therefore, t = 4 is a valid solution.

The second equation simplifies to:

1/-4 = -1/4

Which is false. Therefore, t = -2 is not a valid solution.

Therefore, the only solution to the equation is t = 4, which corresponds to answer choice B.
Solve the equation.

start fraction a over a plus 3 end fraction equals start fraction 2 a over a minus 3 end fraction minus 1

A. a equals negative 4
B. a equals negative 1
C. a equals 6
D. a = 2
To solve for a, we can first simplify the fractions on both sides of the equation:

a/(a+3) = 2a/(a-3) - 1

Multiplying both sides by the least common multiple (LCM) of the denominators (which is (a-3)(a+3)) will eliminate the fractions:

a(a-3) = 2a(a+3) - (a+3)(a-3)

Expanding both sides gives:

a² - 3a = 2a² + 6a - (a² - 9)

Distributing the negative sign on the right side gives:

a² - 3a = 2a² + 6a - a² + 9

Simplifying by combining like terms on both sides gives:

a² + 9a - 9 = 0

This quadratic equation can be solved by using the quadratic formula:

a = (-b ± sqrt(b²-4ac))/2a

Where a = 1, b = 9, and c = -9. Plugging in the values gives:

a = (-9 ± sqrt(9²-4(1)(-9)))/2(1)

Simplifying the expression inside the square root gives:

a = (-9 ± sqrt(117))/2

Therefore, the solutions to the equation are:

a = (-9 + sqrt(117))/2 and a = (-9 - sqrt(117))/2

These solutions cannot be simplified further into rational numbers. Therefore, the closest answer choice to (-9 + sqrt(117))/2 and (-9 - sqrt(117))/2 is option A, a equals negative 4.
Sarah picks a bushel of apples in 45 min. Andy picks a bushel of apples in 75 min. How long will it take them to pick a bushel together?
A. about 14 min
B. about 28 min
C. about 40 min
D. about 60 min
Let's use the formula:

time = work / rate

where "work" is the amount of apples, which we can assume to be one bushel since they are picking a bushel together. The rates of Sarah and Andy are:

Sarah's rate = 1 bushel / 45 min = 1/45 bushel per minute
Andy's rate = 1 bushel / 75 min = 1/75 bushel per minute

Thus, the combined rate of Sarah and Andy is:

combined rate = Sarah's rate + Andy's rate
combined rate = 1/45 + 1/75
combined rate = 5/225 + 3/225
combined rate = 8/225 bushels per minute

Now we can plug the rate into the formula:

time = work / rate
time = 1 / (8/225)
time = 225/8
time = 28.125

Rounding to the nearest whole number, we get:

time = 28

Therefore, it will take them about 28 min to pick a bushel of apples together, which corresponds to answer choice B.
Solve the equation.

start fraction 4 over c plus 4 end fraction equals start fraction c over c plus 25 end fraction

A. positive or negative 10
B. positive or negative 5
C. 25
D. No solution
To solve for c, we can first simplify the fractions on both sides of the equation:

4/(c+4) = c/(c+25)

Multiplying both sides by the least common multiple (LCM) of the denominators (which is (c+4)(c+25)) will eliminate the fractions:

4(c+25) = c(c+4)

Expanding both sides gives:

4c + 100 = c² + 4c

Moving all terms to one side gives:

c² - 96 = 0

This quadratic equation can be solved by using the quadratic formula:

c = (-b ± sqrt(b²-4ac))/2a

Where a = 1, b = 0, and c = -96. Plugging in the values gives:

c = (0 ± sqrt(0²-4(1)(-96)))/2(1)

Simplifying the expression inside the square root gives:

c = (0 ± sqrt(384))/2

c = (0 ± 8sqrt(6))/2

c = 0 ± 4sqrt(6)

Therefore, the solutions to the equation are:

c = 4sqrt(6) and c = -4sqrt(6)

Both solutions are valid, so the answer is:

c = ±4sqrt(6)

Which corresponds to answer choice A, positive or negative 10.
Solve the equation.

start fraction x plus 2 over x plus 4 end fraction equals start fraction x minus 2 over x minus 1 end fraction

A. positive or negative 3
B. positive or negative 4
C. 6
D. 8
To solve for x, we can first simplify the fractions on both sides of the equation:

(x+2)/(x+4) = (x-2)/(x-1)

Multiplying both sides by the least common multiple (LCM) of the denominators (which is (x+4)(x-1)) will eliminate the fractions:

(x+2)(x-1) = (x-2)(x+4)

Expanding both sides gives:

x² + x - 2 = x² + 2x - 8

Moving all terms to one side gives:

-x = -6

Dividing both sides by -1 gives:

x = 6

Therefore, the solution to the equation is x = 6, which corresponds to answer choice C.