-3 cos t = 1
cos(t)=-(1/3)
Look at the plot of cos(t) between 0 and 2π, and note that there are two solutions between π/2 and 3π/2 where cos(t) is negative.
solve the equation -3 cos t = 1 in the interval from 0 to 2p?
3 answers
1. function g(x)=-x^2-3x+7 . Find the area under the curve for the domain –4£ x £ 1.
a 71.6 square units
b. 46 square units
c.35.83 square units
d.17.916square units
a 71.6 square units
b. 46 square units
c.35.83 square units
d.17.916square units
∫-x^2-3x+7dx between -4 and 1
to evaluate
[-x³/3-(3/2)x²+7x] between -4 and 1.
to evaluate
[-x³/3-(3/2)x²+7x] between -4 and 1.