did you mean ...
3^(2x) + 2(3^x) - 15 = 0 ?
I will assume you did.
let 3^x = t
your equation becomes
t^2 + 2t - 15 = 0
(t+5)(t-3) = 0
t = -5 or t = 3
then 3^x = -5, which has no solution or
3^x = 3
x = 1
solve the equation 3^2x + 2.3^x - 15 = 0
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