Asked by Ann
                Solve the equation 2x + 5y - 3z = -1. Write the general solution as a matrix equation.
[x] [ ] [1]
[y]= [ ] X [s]
[z] [ ] [t]
I'm supposed to fill in that blank in the middle, but I don't understand how to solve this if I'm only given one equation. please explain
            
            
        [x] [ ] [1]
[y]= [ ] X [s]
[z] [ ] [t]
I'm supposed to fill in that blank in the middle, but I don't understand how to solve this if I'm only given one equation. please explain
Answers
                    Answered by
            Ann
            
    [x]  [...]   [1] 
[y]= [...] X [s]
[z] [...] [t]
to align it better I put dots in the blanks...and I think s and t are free variables that be be any real number
    
[y]= [...] X [s]
[z] [...] [t]
to align it better I put dots in the blanks...and I think s and t are free variables that be be any real number
                    Answered by
            Lane
            
    okay i put it wrong I'm sorry the question said 
Convert to the Alternate form (Exponential INTO logarithm)
    
Convert to the Alternate form (Exponential INTO logarithm)
                    Answered by
            Steve
            
    (2 5 -3) (x y z)<sup>T</sup> = -1
The transpose is for readability, since it has to be a column vector.
    
The transpose is for readability, since it has to be a column vector.
                    Answered by
            Ann
            
    I still don't really understand how to do it...
I did some guessing and ended up getting this much:
[x] [-1/2 _ _] [1]
[y]= [0 1 0] X [s]
[z] [0 0 1] [t]
however I still can't figure out the last two values in the first row.
 
    
I did some guessing and ended up getting this much:
[x] [-1/2 _ _] [1]
[y]= [0 1 0] X [s]
[z] [0 0 1] [t]
however I still can't figure out the last two values in the first row.
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