solve the equation

Question

2 tan^2(theta)sin(theta)-tan^2(theta)=0

interval[0,360)

Answer 1

2 tan^2(theta)sin(theta)-tan^2(theta)=0 , I will use x for theta
tan^2 x(2sinx - 1) = 0
tan^2x = 0 or sinx = 1/2
tanx = 0 or sinx = 1/2

x = 0, 180, 360 or x = 30, 150