First, we can simplify the right side by combining the constants:
y"/y = (-2/9)*(1/(x^2))
Next, we can multiply both sides by y to get:
y" = (-2/9)*(y/(x^2))
This is a second-order linear differential equation, which can be solved using standard techniques such as the characteristic equation or the method of undetermined coefficients. However, without initial or boundary conditions, we cannot determine a unique solution.
Solve the differential equation
y"/y =(-4/18)*(1/(x^2))
5 answers
Initial conditions y(1)=1 and y(8)=4
Thank you for providing the initial conditions. With these conditions, we can find a unique solution to the differential equation.
To solve the differential equation:
1. Rewrite the equation as
y" + (2/9)*(y/(x^2)) = 0
2. Assume a solution of the form
y = x^r
Taking the first and second derivative of y, we get:
y' = rx^(r-1)
y'' = r(r-1)x^(r-2)
3. Substitute this into the differential equation and simplify:
r(r-1)x^(r-2) + (2/9)*x^(-2)*rx^r = 0
r(r-1) + (2/9)*r = 0
Solving for r, we get:
r = 0 or r = -2/9
Thus, we have two linearly independent solutions:
y1 = x^0 = 1
y2 = x^(-2/9)
4. The general solution is a linear combination of these two solutions:
y(x) = C1 + C2*x^(-2/9)
5. Using the initial conditions, we can solve for the constants:
y(1) = C1 + C2*1^(-2/9) = 1
y(8) = C1 + C2*8^(-2/9) = 4
Solving this system of equations, we get:
C1 = 7.581
C2 = -7.220
Thus, the solution to the differential equation with the given initial conditions is:
y(x) = 7.581 - 7.220*x^(-2/9)
To solve the differential equation:
1. Rewrite the equation as
y" + (2/9)*(y/(x^2)) = 0
2. Assume a solution of the form
y = x^r
Taking the first and second derivative of y, we get:
y' = rx^(r-1)
y'' = r(r-1)x^(r-2)
3. Substitute this into the differential equation and simplify:
r(r-1)x^(r-2) + (2/9)*x^(-2)*rx^r = 0
r(r-1) + (2/9)*r = 0
Solving for r, we get:
r = 0 or r = -2/9
Thus, we have two linearly independent solutions:
y1 = x^0 = 1
y2 = x^(-2/9)
4. The general solution is a linear combination of these two solutions:
y(x) = C1 + C2*x^(-2/9)
5. Using the initial conditions, we can solve for the constants:
y(1) = C1 + C2*1^(-2/9) = 1
y(8) = C1 + C2*8^(-2/9) = 4
Solving this system of equations, we get:
C1 = 7.581
C2 = -7.220
Thus, the solution to the differential equation with the given initial conditions is:
y(x) = 7.581 - 7.220*x^(-2/9)
This line is wrong
r(r-1)x^(r-2) + (2/9)*x^(-2)*rx^r = 0
r(r-1)x^(r-2) + (2/9)*x^(-2)*rx^r = 0
I apologize for the mistake in the previous line. The correct line should be:
r(r-1)x^(r-2) + (2/9)*x^(-2)*x^r = 0
Simplifying this equation, we get:
r(r-1) + (2/9)*x^(-2) = 0
Then, solving for r, we have:
r = 0 or r = -2/9
Therefore, we have two linearly independent solutions:
y1 = x^0 = 1
y2 = x^(-2/9)
The general solution is given by:
y(x) = C1 + C2*x^(-2/9)
Using the initial conditions, we can solve for the constants:
y(1) = C1 + C2*1^(-2/9) = 1
y(8) = C1 + C2*8^(-2/9) = 4
Solving for C1 and C2, we get:
C1 = 7.581
C2 = -7.220
Therefore, the solution to the differential equation with the given initial conditions is:
y(x) = 7.581 - 7.220*x^(-2/9)
r(r-1)x^(r-2) + (2/9)*x^(-2)*x^r = 0
Simplifying this equation, we get:
r(r-1) + (2/9)*x^(-2) = 0
Then, solving for r, we have:
r = 0 or r = -2/9
Therefore, we have two linearly independent solutions:
y1 = x^0 = 1
y2 = x^(-2/9)
The general solution is given by:
y(x) = C1 + C2*x^(-2/9)
Using the initial conditions, we can solve for the constants:
y(1) = C1 + C2*1^(-2/9) = 1
y(8) = C1 + C2*8^(-2/9) = 4
Solving for C1 and C2, we get:
C1 = 7.581
C2 = -7.220
Therefore, the solution to the differential equation with the given initial conditions is:
y(x) = 7.581 - 7.220*x^(-2/9)
2 answers