Question

Solve the compound inequality.

-9 (less than or equal to) -3x - 9 (less than or equal to) 15

I totally forget how to solve inequalities, please help! Thanks!

Answer 1

-9<= -3x-9<=15
add 9 to each component.
0<=-3x<=24
divide by -3
0>x>8

check that.

Answer 2

This is what I got:
0(greater than or equal to)x(greater than or equal to) -8
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
(less than or equal to)=(LTorET)
(greater than or equal to)=(GTorET)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
1. I broke it up into 2 problems
-9(LTorET)-3x-9 and -3x-9(LTorET)15

2.I solved the first problem by adding 9 to both sides. Then I had
0(LTorET)-3x

3.I divided both sides by -3 which equaled
0(GTorET)x

~~note: Flip the sign when dividing or multiplying by a negative~~

4. I did the same type of thing with
-3x-9(LTorET)15 which equaled
x(GTorET)-8

5. I got the answer:
0(GTorET)x(GTorET)-8
OR
x(LTorET)0 and x(GTorET)-8


~~however you want to write that~~





If you go to google and look up how to solve compound inequalities there are some good pages there.

Answer 3

-8 on the right is correct.