y = c1 e^-6x + c2 e^x
Plug in your boundary conditions, and you get
c1 + c2 = 0
c1/e^12 + c2/e^2 = 1
Now just solve for c1 and c2
Solve the boundary-value problem.
y'' + 5y' - 6y = 0 , y(0) = 0 , y(2) = 1
1 answer
y'' + 5y' - 6y = 0 , y(0) = 0 , y(2) = 1
1 answer