tan2x = sin2x
sin2x/cos2x = sin2x
sin2x(cos2x-1) = 0
so,
sin2x=0
or
cos2x=1
That help?
Solve tan2x = 5sin2x
Giving all solutions in the interval 0 ≤ x ≤ 180°
2 answers
posting for anyone else who comes across this thread:
tan2x=5sin2x
tan2x=5*tan2x*cos2x
divide both sides by tan(2x)
1=5cos2x
0.2=cos2x
cos^-1 both sides
78.46..=2x
39.2=x
draw cos2x graph. as symmetrical next value = 180-39.2.
and don't forget the values where both = 0
tan2x=5sin2x
tan2x=5*tan2x*cos2x
divide both sides by tan(2x)
1=5cos2x
0.2=cos2x
cos^-1 both sides
78.46..=2x
39.2=x
draw cos2x graph. as symmetrical next value = 180-39.2.
and don't forget the values where both = 0