Solve:

Question

(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)

I do know that (t^2-t-56) can be factored out to (t-8)(t+7) so I have the equation as (t+24/(t-8)(t+7) +7(t+7)/(t-8)(t+7)-3(x-8)/(t-8)(t+7) is this correct ot what am I doing wrong?

Answer 1

Assistance needed.

Answer 2

Solve:
(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)

How do I solve this problem

Answer 3

the common denominator is (t-8)(t+7)

so multipy both sides by

(t-8)(t+7)

(t-24) + 7(t+7)=3(t-8)
solve for t.