Solve:
(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)
I do know that (t^2-t-56) can be factored out to (t-8)(t+7) so I have the equation as (t+24/(t-8)(t+7) +7(t+7)/(t-8)(t+7)-3(x-8)/(t-8)(t+7) is this correct ot what am I doing wrong?
3 answers
Assistance needed.
Solve:
(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)
How do I solve this problem
(t+24)/(t^2-t-56)+7/(t-8)=3/(t+7)
How do I solve this problem
the common denominator is (t-8)(t+7)
so multipy both sides by
(t-8)(t+7)
(t-24) + 7(t+7)=3(t-8)
solve for t.
so multipy both sides by
(t-8)(t+7)
(t-24) + 7(t+7)=3(t-8)
solve for t.