Hmmm. I saw you answered a question on trig, but this one bothers you?
√(2x-3) - 3√(1-x) = 0
√(2x-3) = 3√(1-x)
2x-3 = 9-9x
11x = 12
x = 12/11
Now, see whether that works in the original equation.
It does not, since 2x-3 < 0
Solve (sqrt2x-3)-(3sqrt1-x)=0
2 answers
Thanks for helping me, algebra is just my weakness 😓