Solve sin θ = 0.95 for -90º ≤ θ ≤ 90º. Round to the nearest tenth.

Answer 1

Start drawing these things on paper.
-90 to + 90 is in quadrants 4 to 1
in quadrant 4 the sin of theta is negative, y is down and x is right.
Therefore this is really only from
0º ≤ θ ≤ 90º
sin^-1 0.95 = 71.8 degrees

Answer 2

Thank you so much!