Rewrite this using the trig identity
sec^2(x) = 1 + tan^2(x)
Then treat tanx as a new variable, y
1 + tan^2x = sqrt3*(tanx + 1)
1 + y^2 = sqrt3*(y + 1)
y^2 -sqrt3*y -(sqrt3 -1) = 0
Solve the quadratic equation for y and then use x = arctan y to solve for x
Solve:
sec(x)^2= 3tanx +1
*** It is suppose to be the sqaure root of 3 but i could find the symbol so just wrote the 3 without it but it is suppose to be the square root of 3 times tanx + 1
1 answer
1 answer