solve [(root125)^4]^1/6. so far, I got (6 root root 125)^25 is this correct? Where do I go from here? how can I get rid of two roots?
3 answers
please help me understand this; I have ten more math problems that are similar to still do.
I assume you want to evaluate
[(root125)^4]^1/6 , not "solve" it
recall that (a^x)^y = a^xy
so we get
(root125)^4/6
= ((125)^1/2)^2/3
= 125^1/3
= 5
[(root125)^4]^1/6 , not "solve" it
recall that (a^x)^y = a^xy
so we get
(root125)^4/6
= ((125)^1/2)^2/3
= 125^1/3
= 5
oh, okay, thanks!
1 answer